0.4x^2+1.1x=2

Solution for 0.4x^2+1.1x=2 equation:

0.4x^2+1.1x=2

We move all terms to the left:

0.4x^2+1.1x-(2)=0

a = 0.4; b = 1.1; c = -2;
Δ = b2-4ac
Δ = 1.12-4·0.4·(-2)
Δ = 4.41
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.1)-\sqrt{4.41}}{2*0.4}=\frac{-1.1-\sqrt{4.41}}{0.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.1)+\sqrt{4.41}}{2*0.4}=\frac{-1.1+\sqrt{4.41}}{0.8}
$